Direct link to this answer Find **the line bisecting the two tangent lines**. This line will contain the center point of the circle. Form a right triangle with one of the tangent lines as a leg, the radius line as the other leg, and the bisecting line as the hypotenuse.

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## How do you find the center of a circle with a tangent line?

The formula for the equation of a circle is (x – h)^{2}+ (y – k)^{2} = r^{2}, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

## How do you find the point where tangent meets the circle?

Hi A point of contact between a tangent and a circle is the only point touching the circle by this line, The point can be found either by: equating the equations; The line: y = mx +c The circle: (x-a)^2 + (y_b)^2 = r^2 The result will be the value of {x}which can be substituted in the equation of the line to find

## What is the formula for tangent?

Then the tangent formula is, tan x = (opposite side) / (adjacent side), where “opposite side” is the side opposite to the angle x, and “adjacent side” is the side that is adjacent to the angle x.

## What is the center of the circle?

The center of a circle is the point equidistant from the points on the edge. Similarly the center of a sphere is the point equidistant from the points on the surface, and the center of a line segment is the midpoint of the two ends.